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  1. How do you graph the equation #3x=y#? - Socratic

    Oct 23, 2016 · Well, all you have to do is to plug two values for #x# and find the values of #y# then graph the line. It will surely pass through the origin.

  2. Question #567c3 + Example - Socratic

    Since this line (a hypotenuse) should be equally inclined to both axes, a triangle must have two congruent acute angles of 45^o each. An example of this line is the one going fro point (0,1) to …

  3. A line passes through (2 ,8 ) and (4 ,5 ). A second line passes …

    A line passes through # (2 ,8 )# and # (4 ,5 )#. A second line passes through # (3 ,5 )#. What is one other point that the second line may pass through if it is parallel to the first line? …

  4. Question #8a759 - Socratic

    Explanation: For a., a horizontal line means that the line has a zero slope and thus the equation for this line is #y=-2#

  5. Question #b9b6d - Socratic

    Since the line is parallel to y=2x+1, we know that the line must have a slope of 2, because in function form, the coefficient on x is the line's slope. We know the slope of the line is 2, and we …

  6. Question #6fd4c - Socratic

    Explanation: #"the equation of a line in "color (blue)"slope-intercept form"# is.

  7. How do I answer the following questions? - Socratic

    Therefore, the slope of the line perpendicular will be #-2#. Since the derivative represents the instantaneous rate of change of a function at any point in it's domain, set the derivative to #-2# …

  8. What do you do if you get given an equation to draw a graph

    May 26, 2018 · What do you do if you get given an equation to draw a graph which instead of #y=mx+c# it is #y=8-3#?

  9. Question #90a6b + Example - Socratic

    If a line has the equation y = mx + b, where m and b are constants, then m is the slope of the line and b is the y-intercept (that is, the line passes through the point (0, b)). Note that the given …

  10. Question #d4f64 - Socratic

    The y-intercept is defined to be the point at which the line intersects the y-axis. You can calculate it by substituting #x=0# into the equation: #y=1/4x+1# #y=1#